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9y^2+21y-30=0
a = 9; b = 21; c = -30;
Δ = b2-4ac
Δ = 212-4·9·(-30)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-39}{2*9}=\frac{-60}{18} =-3+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+39}{2*9}=\frac{18}{18} =1 $
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